Home > Unexpected Token > Unexpected Token O Json Parse

Unexpected Token O Json Parse

Contents

share|improve this answer edited Sep 24 '14 at 20:37 answered Jan 21 '13 at 3:40 Onur Yıldırım 12.6k33657 add a comment| up vote 19 down vote I found the same issue You have two options from here: Wait for the promise to resolve and execute on it using .done(). Understanding the grammar: «illis Evangelii nuntiandi praebens mandatum» Is including the key as AAD actually dangerous? Binary to decimal converter Anxious about riding in traffic after 20 year absence from cycling Word that includes "food, alcoholic drinks, and non-alcoholic drinks"? Source

I also tried JSON.stringify(inputString), but it did not help. Thx –Guillaume Jul 9 at 23:24 don't trust a source responding with invalid JSON. jsonStringQuotes = "'" + jsonStringNoQuotes + "'"; will return '[object]' thats why it(below) is causing error var myData = JSON.parse(jsonStringQuotes); share|improve this answer answered Oct 8 '13 at 4:44 Pankaj Sharma The following will fix your sample: As the other respondents have mentioned,

Unexpected Token O Json Parse

What you mean is a "JS object". –Joseph the Dreamer Mar 25 '13 at 14:19 add a comment| up vote 7 down vote The source of your error, however, is that It does the JSON parsing even though you're not calling getJSON()-- then when you try to call JSON.parse() on an object, you're getting the error. asked 3 years ago viewed 97500 times active 11 months ago Visit Chat Linked 225 I keep getting “Uncaught SyntaxError: Unexpected token o” 52 Uncaught SyntaxError: Unexpected token with JSON.parse 0

The error is as follows: Uncaught SyntaxError: Unexpected token o (anonymous function)script.js:10 jQuery.Callbacks.firejquery-1.7.js:1064 jQuery.Callbacks.self.fireWithjquery-1.7.js:1182 donejquery-1.7.js:7454 jQuery.ajaxTransport.send.callback My javascript code is contained in a separate file and is simply this: function loadPageIntoDiv(){ Unable to understand the details of step-down voltage regulator How to write an effective but very gentle reminder email to supervisor to check the Manuscript? Idiomatic Expression that basically says "What's bad for you is good for me" What are the downsides to multi-classing? Uncaught Syntaxerror Unexpected Token Jquery Json more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed

JSON is a string. Uncaught Syntaxerror Unexpected Token Json Parse Join them; it only takes a minute: Sign up Uncaught SyntaxError: Unexpected token o : Simple JSON parser not working [duplicate] up vote -2 down vote favorite This question already has I solved it by doing a JSON.stringify before doing a JSON.parse. –arrow May 16 '14 at 18:57 Same as people here, I wasted an hour wandering around there and TV episode or movie where people on planet only live a hundred days and fall asleep at prescribed time French vs Italian resistance Should a country name in a country selection

Reload to refresh your session. Json Parse Unexpected Token End Of File At Position 0 Their syntax is precisely where JSON got its. This is the .json file: [ { "name": "Alabama", "abbreviation": "AL" }, { "name": "Alaska", "abbreviation": "AK" }, { "name": "American Samoa", "abbreviation": "AS" }, { "name": "Arizona", "abbreviation": "AZ" }] I understand this more now. –Zapp Aug 28 '15 at 18:15 add a comment| up vote 0 down vote Before JSON.parse(), just check typeOf obj==='object'.

Uncaught Syntaxerror Unexpected Token Json Parse

Try just using the file i.e. Your last one is definitely incorrect. –user2736012 Oct 8 '13 at 4:47 You need to post some actual data and code. –user2736012 Oct 8 '13 at 4:52 Unexpected Token O Json Parse For information about the arguments this function receives, see the jqXHR Object section of the $.ajax() documentation. Uncaught Syntaxerror Unexpected Token In Json Is the partition function of non-conformal theories on a torus modular invariant?

Try our newsletter Sign up for our newsletter and get our top new questions delivered to your inbox (see an example). this contact form Help my maniacal wife decorate our christmas tree Square root image filter tool in Python Removing brace from the left of dcases Hit a curb today, taking a chunk out of Make text field readonly Can a free radical be created by chemical reaction of non-radical species? Unable to understand the details of step-down voltage regulator Hit a curb today, taking a chunk out of the tire and some damage to the rim. Syntaxerror Unexpected Token In Json At Position

As of jQuery 1.9, an empty response is also rejected; the server should return a response of null or {} instead. (See json.org for more information on proper JSON formatting.) "jsonp": please read my answer again –Pankaj Sharma Oct 8 '13 at 5:09 Sorry, I missed "no" in "no need to parse" (early morning here). share|improve this answer answered Oct 26 '14 at 12:19 Scimonster 18.6k43369 So how would I get the value for type? –CodyBugstein Oct 26 '14 at 12:27 @Imray: have a peek here Join them; it only takes a minute: Sign up Uncaught SyntaxError: Unexpected token with JSON.parse up vote 52 down vote favorite 14 what causes this error on the third line?

For example, using jQuery get method: $.get('/service', function(data) { var obj = data; /* "obj" is evaluated at this point if server responded with "application/json" or similar. */ for (var i Unexpected Token O In Json At Position 0 more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed When I remove the json file I get the error: "GET http://.../wokab.json 404 (Not Found)" so I know it's loading it (or at least trying to).

Remnants of the dual number Rebus: Guess this movie Why are terminal consoles still used?

keys must be quoted Correct JSON { "english": "bag", "kana": "kaban", "kanji": "K" } Error JSON 1 { 'english': 'bag', 'kana': 'kaban', 'kanji': 'K' } Error JSON 2 { english: "bag", Is there any financial benefit to being paid bi-weekly over monthly? VT-x is not available, but is enabled in BIOS Need a way for Earth not to detect an extrasolar civilization that has radio Schengen visa to Norway to visit my wife Json.parse Unexpected Token U The jqXHR.done() (for success), jqXHR.fail() (for error), and jqXHR.always() (for completion, whether success or error) methods take a function argument that is called when the request terminates.

This is illegal. For example, var str = "{"a":1,"b":2}"; var obj = JSON.parse(str); //obj = {a:1, b:2} Reference MDN share|improve this answer edited Sep 24 '13 at 3:04 answered Sep 24 '13 at 2:49 Cross-domain "json" requests are converted to "jsonp" unless the request includes jsonp: false in its request options. Check This Out If JSON response is detected, deserialize it using a JSON parser.

Will majority of population dismiss a video of fight between two supernatural beings? if you parse it again it will give you "unexpected token o" however you have to specify datatype in your request to be of type dataType='json' share|improve this answer edited Aug Thanks for the pointer I'll keep it in mind. –Bjorninn Nov 21 '11 at 14:52 add a comment| up vote 1 down vote Simply the response is already parsed, you don't For example, if you want a text response to be treated as XML, use "text xml" for the dataType.

If none is specified, jQuery will try to infer it based on the MIME type of the response (an XML MIME type will yield XML, in 1.4 JSON will yield a Alternatively, you can follow these instructions to delete the incorrectly set localStorage value. Similarly, a shorthand string such as "jsonp xml" will first attempt to convert from jsonp to xml, and, failing that, convert from jsonp to text, and then from text to xml.